列 现在有2个数组
var
date = [
"1970-01-01"
,
"1970-01-22"
,
"1970-06-09"
,
"1971-02-11"
,
"1971-02-21"
,
"1971-03-01"
,
"1971-05-06"
,
"1972-06-02"
,
"1973-05-18"
,
"1973-11-20"
,
"1973-12-15"
,
"1974-03-12"
,
"1974-03-14"
,
"1975-03-08"
,
"1975-05-01"
,
"1975-07-01"
,
"1976-02-09"
,
"1976-02-17"
,
"1976-02-21"
,
"1976-10-08"
,
"1977-03-06"
,
"1977-12-06"
,
"1978-02-16"
,
"1978-10-10"
,
"1978-10-11"
,
"1978-10-27"
,
"1978-11-20"
,
"1978-12-02"
,
"1978-12-12"
,
"1979-06-07"
,
"1979-10-29"
,
"1980-02-11"
,
"1980-08-01"
,
"1980-09-01"
,
"1980-09-05"
,
"1980-11-02"
,
"1980-11-06"
,
"1980-11-15"
,
"1980-12-05"
,
"1981-03-08"
,
"1981-11-03"
,
"1981-12-07"
,
"1981-12-19"
,
"1982-01-22"
,
"1982-10-04"
,
"1983-02-21"
,
"1983-09-18"
,
"1983-09-26"
,
"1983-11-03"
,
"1984-09-15"
,
"1984-11-06"
,
"1985-03-04"
,
"1985-07-10"
,
"1985-12-10"
,
"1986-04-19"
,
"1986-05-03"
,
"1986-05-08"
,
"1986-06-07"
,
"1986-08-06"
,
"1986-10-15"
,
"1986-12-01"
,
"1986-12-17"
,
"1987-01-09"
,
"1987-02-16"
,
"1987-03-06"
,
"1987-05-14"
,
"1987-06-03"
,
"1987-07-07"
,
"1987-08-31"
,
"1987-09-25"
,
"1987-10-09"
,
"1987-11-13"
,
"1987-11-19"
,
"1987-12-14"
,
"1988-01-16"
,
"1988-04-01"
,
"1988-04-13"
,
"1988-05-06"
,
"1988-05-20"
,
"1988-06-04"
,
"1988-06-12"
,
"1988-06-14"
,
"1988-08-20"
,
"1988-10-29"
,
"1989-01-11"
,
"1989-01-28"
,
"1989-04-26"
,
"1989-06-16"
,
"1989-07-12"
,
"1989-07-14"
,
"1989-08-25"
,
"1989-10-26"
,
"1989-10-30"
,
"1990-01-02"
,
"1991-01-18"
,
"1991-02-14"
,
"1991-02-27"
,
"1991-03-16"
,
"1991-05-13"
,
"1991-06-28"
,];
count=[1,
1,
1,
1,
1,
1,
1,
1,
1,
1,
1,
2,
1,
1,
2,
2,
1,
1,
1,
1,
1,
1,
1,
1,
1,
1,
1,
1,
1,
1,
1,
1,
1,
1,
1,
1,
1,
1,
1,
1,
1,
3,
2,
1,
1,
1,
1,
1,
1,
2,
1,
1,
1,
1,
1,
1,
1,
1,
1,
1,
1,
1,
1,
1,
1,
1,
1,
1,
1,
1,
1,
1,
1,
3,
2,
1,
1,
1,
1,
1,
1,
2,
1,
1,
1,
1,
1,
1,
1,
1,
1,
2,
1,
1,
1,
1,
1,
1,
1,
1,];
然后补齐date数组中缺少的日期 然后新插入的日期对应的count设置为0